Why current is steady @ Pinchoff voltage ?

I was studying the JFET. In the books and other material it is mentioned that when the voltage between the drain and source is increased then drain current is also increased. After a certain point (Pinch Off) the drain current becomes constant and will remain constant even if the drain voltage is increased. If we see the physical structure of the device the depletion region will start to increase when the voltage between the drain and source is increased. After the same certain point (Pinch off Point)depletion region touches and then current cannot move forward.

My question here is that then how the current becomes steady or current will pass when the depletion regions are closed. Doesn't the current become zero ?

If the depletion region is closed by Voltage between drain and source then what is the role of voltage between gate and source. Although I can see the steady current value is changed at different Voltage gate to source and a logic of faster build of depletion region (Through Voltage to Source and Drain to source) also comes in mind but what is the main logic behind it ?

Before replying please consider me as basic learner. Thanks

It is steady because the region cannot be increased further.  Current is a physical thing-  electrons flowing.  only so many electrons and corresponding holes exist in the doping region, so when maximum attraction and maximum transconductivity occur, that's all you can get

  Joined November 18, 2019      8
Monday at 02:06 AM