# Understanding current flow in a circuit and i=q/t

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Joined: Jul 28, 2019

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Understanding current flow in a circuit and i=q/t
July 28, 2019 - 10:07pm

Hello,im a total beginner in electronics and there is something i don't understand.The problem started when i read a youtube comment made by a youtuber called ElectroBoom(he has a master degree in electronics).In the comments he said some other youtuber was mistaken about something he said in a video.And in his explanation about why is he wrong,i found something that i can't understand.The comment went like this :"....This is because current=charge/time.*Since time is very short,the current is high*...."And the marked sentence (with *) is what i don't understand.I understood what he said,as that current in a circuit decreases with time?I always thought that current flow in a normal circuit is constant,like a battery that's pushing constant 10 Amps(if we consider that nothing is changing in the circuit while it's running) until the battery dies out and the load( a light bulb for example) stops working.Also,i've been always understanding the i=q/t formula like this;If the amount of charges is a 100C for example,and the time is 1sec,then the current shall be i=100/1,so i=100Amps.And if the time is 2secs,then the number of charges that passed through a cross sectional area should also double?Meaning i=200C/2secs,so current is still constant,and "i" is still 100Amps?The main point i need clarified here is,is the current that passes through a circuit constant,until the energy source dies out?Exp. 100amps goes through a circuit until the battery is dead.I know maybe this all sounds stupid but i'd be thankful if someone could explain,as i want to truly understand how electronics work.