I am not sure how to wire for input and load on my mini mechanical relay. My2NJ Mini Relay. DPDT 8 pins 10AHH52P JQX-13F with PYF08A Socket.
Socket screw terminals look like this:
(04) (01)
(08) (05)
(12) (09)
(14) (13)
Thanks
GreySmoke
Can you share images and datasheet or exact partnumber. What you want to do?
I'm going ac to ac. My load would go to 5 and 9. This is normally open? And my input is 13 and 14 with 14 being the hot wire. Am I reading this correctly?
5 and 9 is normaly open switch
You can move Load behind 5 insted in front of 9 in case you need high side switching - depends on your needs (common point)
14 hot is ok
You can use same source for control and for load if your aplication and relay type alow you.
Change the coil controll supply source according your relay type (AC or DC) (voltage level).
Also type of supply voltage (AC or DC) for your load.
Some types of these relays has inverted 13,14 pins, so polarize your control (coil) voltage correct.
Your reading is correct.. Make sure that the load does not exced the rating of the relay. Choose proper voltage for the the relay coil.
GreySmoke
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