I have a load powered by a 9 volt source. The circuit is a simple series circuit. The curcuit has a current of 180 Mille amps. If I were to power the load with a 12 volt source, what resistance would I have to put in series to bring the voltage down to 9 volts. Thanks Gary
Hi Gary! This is not a good practice to use fixed value resistors for reduction of voltage in DC circuit. For the purpose of controlling voltage, you need to use fixed value voltage regulators like 7809 or zener diode of value 9V. You can use any of the above two. Here I would like to recommend you to get connect with the technical support team of SSLA for getting better assistance regarding your projects.
Hi Gary! This is not a good practice to use fixed value resistors for reduction of voltage in DC circuits. For the purpose of controlling voltage, you need to use fixed value voltage regulators like 7809 or zener diode of value 9V. You can use any of the above two. Here I would like to recommend you to get connected with the technical support team of Sierra Software Ltd. for getting better assistance regarding your projects.
How to Reduce Voltage in Half. To reduce voltage in half, we simply form a voltage divider circuit between 2 resistors of equal value (for example, 2 10KΩ) resistors. To divide voltage in half, all you must do is place any 2 resistors of equal value in series and then place a jumper wire in between the resistors.
Gary Gauthier
PermalinkThank you very much Ashutosh for the information, much appreciated Gary
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